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i just don't get what i'm doing wrong... i know the formula, but my answer is wrong..
Everyone, thank you so much!!!! This is on my final exam in like 2 days... i hate math so much, but yes... the answer was 3. |
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Let s = speed of stream
v = speed of boat downstream speed = v + s and upstream speed = v - s 4 ( v + s) = 36 12 - 4 = 8 hours to go upstream 8 ( v - s) = 36 8 ( v + s) = 72 16v = 108 v =108/16 = 27/4 = 6.75 mph v + s = 9 s = 9 - 6.75 = 2.25 mph Ans 2.25mph |
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So the boat goes 36/4 miles per hour downstream (9 mph) and
36/12 mph upstream (3 mph) So the difference is 6 mph. I would think that the stream would increase the boat's speed downward by 3 mph and impede it by 3 mph when it goes upstream. So, what is the answer? |
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Suppose the boat can travel x miles per hour in still water. And the speed of the current is y miles per hour.
Note that when traveling downstream the speed of the boat relative to the bank is x + y. when traveling upstream the speed of the boat relative to the bank is x - y. So we can set up a system of two equations: 4(x + y) = 36 12(x - y) = 36 simplifying them, we have x + y = 9 x - y = 3 Adding them together, we get 2x = 12 x = 6 y = 9 - x = 9 - 6 = 3 So the speed of the current is 3 miles per hour |
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speed=distance/time
However you have to combine velocities of the stream and the boat when going downstream and subtract when going upstream so 36/4 = x + y where x is the boat's speed and y is the stream's speed 36/12 = x - y going downstream Now u have a system of equations 9 = x + y and 3 = x - y use one of the many ways to solve e.g. elimination, matrix, substitution, etc. i'll use elimination: 9+3 = x + x + y - y 12 = 2x x=6 so the boat is moving at 6 mph now find y 9 = 6 + y so y = 3 The stream's speed is 3 mph. |
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let speed of boat be x
speed of stream be y speed downstream = x+y speed upstream = x-y speed = dist./time x+y =36/4 = 9 miles per hr x-y = 36/12 = 3 miles per hr so, x + y =9 x - y = 3 2x = 12 x=6 x +y =9 6+y= 9 y=3 miles per hr ans- speed of stream = 3 miles per hr |
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