Train A and B are traveling in the same direction on parallel tracks.?

Train A and B are traveling in the same direction on parallel tracks. Train A is traveling at 80 miles per hour and train B is traveling at 96 miles per hour. Train A passes a station at 4:20pm. If train B passes the same station at 4:35pm., at what time will train B catch up to train A?
When will train B catch up with train A?

Hi!
I got train B will catch up with train A at 4:55PM. Right? Thanks!

wait, is this a trick question? If they both trains are headed in the same direction, and train B is traveling faster than train A, train B shouldn't have to catch up to train A, it should already be ahead.

distance = rate x time

Using that the are at the same place at the station,
you can use:

Train A's distance = Train B's distance
80t = 96(t - 15)
80t = 96t - 1440
-16t = - 1440
t = 90 minutes, or 90 minutes later

For Train B,
4:35PM + 90 minutes
= 4:35PM + 1 hr 30 minutes
= 6:05PM

Let A and B meet after t hour after departure of A. Then they also meet after t−1/4 hour after departure of B. Also when they meet, they will have traveled same distance.
Distance=Speed×Time.
∴80t=96(t−1/4)
16t=24
t=3/2 hour=1 hour 30 minute
So they meet at 1 hour and 30 minute after 4:20pm. i.e., at 5:50pm. I think you made some mistake but I hope its clear. You must have realized that 1/4 is 15min in hours. I used it since it is more easy to calculate. Note that if you took t as time after departure of B, consequently in similar steps you will get t=5/4hr or 1hr 15min

No. of hrs train B catches up (x):
80x + 15/60(80) = 96x
80x + 20 = 96
16x = 20
x = 5/4 or 1 1/4 hours or 1 hr and 15min

Train B catches up at what time:
= 4:35 PM + 1:15
= 5:50 PM

answer: 5:50 PM

Check (distances covered must be equal)
1 1/2 hr(80 mph) = 1 1/4 hr(96mph)
3/2 hr(80 mph) = 5/4 hr(96 mph)
120 mi = 120 mi