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let t equal the time (in hours) it takes train 1 to travel to the other city. Therefore:
(t)(90kph) = (t +2.5)(50kph) thus: 90t = 50t + 125 thus: 40t = 125 thus: t = 3.125 hours Now just multiple 3.125 hours times 90kph to get 281.15 kilometers We can check our answer by solving for train 2: (3.125 hours + 2.5 hours)(50kph) = (5.625)(50) = 281.25 kilometers {the same answer!} Best wishes and good luck. |
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