Train A and B are traveling in the same direction on parallel tracks...?

Train A is traveling at 60 mph and train B is traveling at 80 mph. Train A passes a station at 11:10 AM. If train B passes the same station at 11:25 AM, at what time will train B catch up to train A?


OK, I know that they are 15 minutes apart but... I don't know what time train B with catch up to train A.

Do you?

in that 15 minutes after A passes the station, it travelled 60*15/60 miles = 15 miles
so, when B reaches the station, A is 15 miles ahead
now B is faster than A by 80 -60 = 20 mph
so to make up 15 miles, B would take 15/20 hrs = 3/4 hrs = 45 minutes
so B will catch up to A by 11:25 + 45 minutes = 12:10

Train A is 15 miles ahead. Train B has 20 mph on Train A, and will close this gap in 15/20 hours, or 45 minutes.
That will happen at 12:10.

Train B will catch up with Train A at 12:10, which is one hour after Train A passed the station.

I think this might be right.
I calculated how far each train would go every 15 minutes.
At 11:25 Train A at station, Train B 15 miles from station
At 11:40 Train A 20 miles from station, Train B 30 miles from station.
At 11:55 Train A 40 miles from station, Train B 45 miles from station.
At 12:10 Train A 60 miles from station, Train B 60 miles from station.

So 12:10 is the answer I think.
Maybe there's an easier way to do it though.