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An express train travels 600 miles in the same amount of time it takes a freight train to travel 360 miles. The rate of the express train is 20 mph faster than that of the freight train. Find the rate of each train.
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Let x be the rate of the freight train, then
x+20 = rate of the express Remember that distance = rate x time time, t = d/r, distance/rate by algebraic manipulation 600 = (x+20)t, or t = 600/(x+20) 360 = xt, or t = 360/x But since t=t, then 600/(x+20) = 360/x (x+20)(360) = 600x 360x + 7200 = 600x 240x = 7200 x = 7200/240 = 30 mph the freight x+20 = 50 mph the express |
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