Find the length of the train travelling at 54km/h passes a passenger in 8 sec .speed of passenger is 72km/h?

A passenger train traveled at 72km/h. A man on the passenger train observed a train traveling at a speed of 54km/h. in opposite direction. if the train passed him in 8 secs, find the length of the train.

My calculations lead to an approx. 840foot train.

Sounds bizarre, but its what I got

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yes but .28km is equivelent to 280m and 280meters is just about 840 feet, Im not gonna count the extra 4 inches a meter, so I guess I was pretty much right, ty man

[(8/3600)(h)][(74+54)(km/h)] = 0.2844 km, the length of the train.

s=vt
s=(54)(8)

when v = 72

s=vt
(54)(8) = 72t
t = 6 sec

They traveled against each other for a total of 126 km/hr. The time is 8 sec. Therefore,

d = distance they traveled until they passed each other (or, Length of train)
r = 126 km/hr
t = 8 sec

We then use the distance formula:

d = rt
d = (126 km/hr)(8 sec)

We multiply constants
(1 min/60 sec)
(1 hr/ 60 min)
(1000 m/1 km)

d = (126 km/hr)(8 sec)(1 min/60 sec)(1 hr/ 60 min)(1000 m/1 km)

d = 280 meters ^_^

The length of the train is 280 meters.
^_^

To find the speed at which the other train moves relative to the man you must add the speeds together. So 54+72=126km/h. Now, change to m/s. 126km/hr * 1hr/60min * 1min/60sec * 1000m/1km = 35m/s. So in 8 seconds... 35m/s * 8s = 280m. The train is 280 meters long (which is 918.64 feet).

The relative speed of the two trains
=72+54
=126 kmh
Therefore,distance travelled in 8 sec
=(8*126*1000/60*60 m
=280 m
The length of the train is 280 m

The relative speed of the passenger train(p) w.r.t other train(t) is

v(pt,t)=v(pt) - v(t)

Consider velocity of passenger train towards positive x-axis and that of other train towards negative x-axis

=>v(pt,t)=72 - (-54)=126 km/hr

=>Dist=126 * 8/(60*60)=0.28 km

=280 m

x = (72*8)+(54*8)=1008