Really hard math problem about space travel?

A spaceship must go 70 million lightyears away in 3 years. How fast must the spaceship go in MPH. Whole numbers please, no exponents

If we just do straight Newtonian Physics then you must travel 70/3 = 23.33 million lightyears / year

Of course that is faster than the speed of light so you must use relativity which means that to people on earth it would still take you 70 million years to get there, but if you were travelling at 99.98% the speed of light then it would only take you 3 years of your time. (If I did that right).

Correction I looked it up and the equation says 99.999999999999% the speed of light to get 70 million light years compressed to 3 light years.

15658.55404 Teramiles / hour

which is

15658554040 million MPH

A lightyear is (thanks to a quick search on Yahoo.com) 5,878,482,164,161.29785 miles. So 70 million lightyears is 70 times that, or 411,493,751,491,290.8495 miles.

1 year is 365.25 days, so 3 years is 3 * 365.25 * 24 = 26,298 hours.

Divide the miles by the hours, and you'll have the speed in MPH.

let's see
a light year is 9,460,730,472,580.8 km
which is 5,878,897,915,661.7 miles
times 70 million
divided by
3 years which is 26,280 hours
gives you 15,659,164,919,951,255.7 miles per hour

Nothing can travel faster than the speed of light...but supposing it is possible:

a) 1 light year is 5.87849981 × 10^12 miles, or 5,878,499,810,000 miles.

b) Each year, the spaceship has to travel 20,333,333.33 light years, or, 1.19529496 × 10^20 miles, or 1,195,294,960,000,000,000,000 miles.

c) Each year has this many hours:
(24)(365.25) = 8766 hours

d) So now we divide the total distance needed to travel by the time were given, so thats:
(1.19529496 × 10^20)/(8,766) = 1.36355802 × 10^16, or in MPH, it is:

13,635,580,200,000,000 miles per hour (This is assuming there are no "official" leap years to deal with)