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Yes, it goes up, but then sea water gets evaporated and sea level goes down, but then there is rain and sea level goes up, then there is storm that takes water on shore which makes sea level goes down... and so on. There is no way you can measure how much it goes up because the ocean is too big, too many things are happening to distract the measurement of the drop, and the water is not still. So give it up!
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The surface of the pacific covers an area of 179,7 Million km². A (very, very big, just to get the order of the amount of the raise of the waterlevel...) drop of water would be 1 ml (approx 1cm^3). So the additional layer of water has a height of:
h = Volume of the drop / Surface of the pacific = 1*10^(-6) m^3 / 1.797*10^14 m^2 = 5.56*10^(-21) m The Bohr atom radius is 10^10 tims larger ... please anyone check the numbers and/or convert it to miles and inches, I'm european ;) and already had a glass (ooops, a non SI unit) of wine ;) Compared to all the rivers that end up in the pacific and the evaopratin, no, you don't have the slightest chance to measure that effect. |
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The obvious answer would be yes, it goes up by a tiny, inmeasureably small amount.
Howver, the answer could depend on how the water drop was added. For example, if someone was out in a boat in the middle of the ocea with a water dropper, the boat's mass, the person's mass, and the mass of the water are all being supported by the boyancy force caused by the displacement of water of the boat. When the droplet leaves the dropper in the boat and falls toward the water, the boat rises up out of the water ever so slightly since that much less water is needed to support the boat. Meanwhile, as the water droplet hits the ocean, the water level raises back up again by the same amount the water level prevously dropped. A net change of zero in the height of the water. |
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