![]() |
![]() |
|
|
|||
|
The viewing portion of the rectangular glass window in a typical fish tank at the New England Aquarium inBoston is 63 in wide and runs from 0.5 inches below the water's surface to 33.5 inches below the surface. The weight-densit of seawater is p= 64lb/ft^3. Find the fluid force against the viewing portionof the window. (Be careful of your units).
|
| Sponsored Links |
|
|
|
|||
|
P=hpg, where
P=pressure at height h. p= density g=acceleration due to gravity F=int P dA, where A is area the pressure is acting on. = int hpg w dh, where w is 63 in. = pgw int h dh from 0.5 to 33.5 in = pgw (h^2)/2 from 0.5 to 33.5 in = pgw [ (33.5^2 - 0.5^2)/2] Be careful of your units. |
![]() |
| Thread Tools | |
| Display Modes | |
|
|