An emitted electron travels at 1.2x10^8ms^-1 for a distance of 0.94 before being absorbed by the air.?

Use Ek =1/2mv^2 to calculate the kinetic Energy of the electron
Also
Use V=d/t to calculate the time the electron is travelling through the air.

Please help

Ek=1/mv^2= 1/2(9.11 x 10^-31)(1.2x10^8)^2=6.55x10^-15kgm-m^2/sec^2

t= d/v = .94/1.2x10^8 =7.833x10^-9sec