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Your given equation is
h = -8t^2 + 40. and to fill up the table (in your question #1), all you have to do is substitute the various values of "t" and calculate for the corresponding values of "h". You should be able to do this on your own because this is a basic algebraic process. Your problem here involves Differential Calculus so I will assume that you know how to do all the simple algebra portions of the problem. 2) To determine the time when the ball reaches its maximum height, differentiate your original function as in (dh/dt) = -16t + 40 and when the ball reaches its maximum height, (dh/dt) = 0 therefore -16t + 40 = 0 and solving for "t" t = 40/16 = 2.5 sec. 3) The maximum height that the ball will attain is h = -8(2.5)^2 + 40(2.5) h = -50 + 100 h = 50 feet |
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